x^2-9=(x-2)(x-5)

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Solution for x^2-9=(x-2)(x-5) equation: 



x^2-9=(x-2)(x-5)

We move all terms to the left:

x^2-9-((x-2)(x-5))=0

We multiply parentheses ..

x^2-((+x^2-5x-2x+10))-9=0



We calculate terms in parentheses: -((+x^2-5x-2x+10)), so:

(+x^2-5x-2x+10)

We get rid of parentheses

x^2-5x-2x+10

We add all the numbers together, and all the variables

x^2-7x+10

Back to the equation:

-(x^2-7x+10)



We get rid of parentheses

x^2-x^2+7x-10-9=0

We add all the numbers together, and all the variables

7x-19=0

We move all terms containing x to the left, all other terms to the right

7x=19

x=19/7

x=2+5/7

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